Aaaamazing
Thanks you.
That worked.
You are correct, the $FFwfDoc.inputFileName$ is the filename for each job's file.
When you submit a zip file the jobs within the zip file are submitted as a job group.
The zip filename is used as the job group name
If you want to use the job group name for naming the file then use that variable: $FFwfJob.groupName$
I'm looking for a variable that will grab the name of the input .ZIP file used in a ganged workflow. I'm saving an imposition file output that I want to be named the input file + "_Impo".
Example: Job 95552 is used for the input .Zip file name, "95552.zip", the zip contains 5 business card the workflow gangs. It saves an imposition file out where I specifiy. I want the file to be named "95552_Impo".
I can only seem to find "$FFwfDoc.inputFileName$", which grabs what seems like a random file name from inside the .zip file.